For any pair define $ c_i = \min\{a_i, b_i\} $ and $ C_n = c_1 + \cdots + c_n $, $ n = 1, 2, \ldots $.
(1) Does there exist a pair $(a_{i})_{i\geq1}$, $(b_{i})_{i\geq1}$ such that the sequences $(A_{n})_{n\geq1}$ and $(B_{n})_{n\geq1}$ are unbounded while the sequence $(C_{n})_{n\geq1}$ is bounded?
(2) Does the answer to question (1) change by assuming additionally that $b_{i}=1/i$, $i=1,2,\ldots?$
Let $\mathbb{R}^{+}$ be the set of all positive real numbers. Find all functions $f\colon \mathbb{R}^{+} \longrightarrow \mathbb{R}^{+}$ that satisfy the following conditions:
(i) $$ f(x y z)+f(x)+f(y)+f(z)=f(\sqrt{x y})f(\sqrt{y z})f(\sqrt{z x}){\text{for all }}x,y,z\in\mathbb{R}^{+} $$
(ii) $ f(x) \lt f(y) $ for all $ 1 \leq x \lt y $.
Let $n$ be a positive integer and let $(x_1, \ldots, x_n)$, $(y_1, \ldots, y_n)$ be two sequences of positive real numbers. Suppose $(z_2, \ldots, z_{2n})$ is a sequence of positive real numbers such that
$$ z_{i+j}^{2}\geq x_{i}y_{j}\qquad\text{for all }1\leq i,j\leq n. $$
Let $ M = \max\{z_2, \ldots, z_{2n}\} $. Prove that
Let $A$ be a 101-element subset of the set $S = \{1,2,\ldots,1000000\}$. Prove that there exist numbers $t_{1}, t_{2}, \ldots, t_{100}$ in $S$ such that the sets
Let $D_{1}, \ldots, D_{n}$ be closed discs in the plane. (A closed disc is the region limited by a circle, taken jointly with this circle.) Suppose that every point in the plane is contained in at most 2003 discs $D_{i}$. Prove that there exists a disc $D_{k}$ which intersects at most $7\cdot2003-1$ other discs $D_{i}$.
Let $n \geq 5$ be a given integer. Determine the greatest integer $k$ for which there exists a polygon with $n$ vertices (convex or not, with non-selfintersecting boundary) having $k$ internal right angles.
Suppose that $B$ is an $n \times n$ matrix with entries 0, 1 such that the sum of the elements in each row and each column of $B$ is equal to the corresponding sum for the matrix $A$. Prove that $A = B$.
Let $ABCD$ be a cyclic quadrilateral. Let $P, Q, R$ be the feet of the perpendiculars from $D$ to the lines $BC, CA, AB$, respectively. Show that $PQ = QR$ if and only if the bisectors of $\angle ABC$ and $\angle ADC$ are concurrent with $AC$.
Three distinct points $A$, $B$, $C$ are fixed on a line in this order. Let $\Gamma$ be a circle passing through $A$ and $C$ whose centre does not lie on the line $AC$. Denote by $P$ the intersection of the tangents to $\Gamma$ at $A$ and $C$. Suppose $\Gamma$ meets the segment $PB$ at $Q$. Prove that the intersection of the bisector of $\angle AQC$ and the line $AC$ does not depend on the choice of $\Gamma$.
Let $ABC$ be a triangle and let $P$ be a point in its interior. Denote by $D$, $E$, $F$ the feet of the perpendiculars from $P$ to the lines $BC$, $CA$, $AB$, respectively. Suppose that
$$ AP^{2}+PD^{2}=BP^{2}+PE^{2}=CP^{2}+PF^{2}. $$
Denote by $ I_{A} $, $ I_{B} $, $ I_{C} $ the excentres of the triangle ABC. Prove that P is the circumcentre of the triangle $ I_{A}I_{B}I_{C} $.
Let $\Gamma_{1}$, $\Gamma_{2}$, $\Gamma_{3}$, $\Gamma_{4}$ be distinct circles such that $\Gamma_{1}$, $\Gamma_{3}$ are externally tangent at $P$, and $\Gamma_{2}$, $\Gamma_{4}$ are externally tangent at the same point $P$. Suppose that $\Gamma_{1}$ and $\Gamma_{2}$; $\Gamma_{2}$ and $\Gamma_{3}$; $\Gamma_{3}$ and $\Gamma_{4}$; $\Gamma_{4}$ and $\Gamma_{1}$ meet at $A$, $B$, $C$, $D$, respectively, and that all these points are different from $P$.
Let $ABC$ be an isosceles triangle with $AC = BC$, whose incentre is $I$. Let $P$ be a point on the circumcircle of the triangle $AIB$ lying inside the triangle $ABC$. The lines through $P$ parallel to $CA$ and $CB$ meet $AB$ at $D$ and $E$, respectively. The line through $P$ parallel to $AB$ meets $CA$ and $CB$ at $F$ and $G$, respectively. Prove that the lines $DF$ and $EG$ intersect on the circumcircle of the triangle $ABC$.
Let $ABC$ be a triangle with semiperimeter $s$ and inradius $r$. The semicircles with diameters $BC$, $CA$, $AB$ are drawn on the outside of the triangle $ABC$. The circle tangent to all three semicircles has radius $t$. Prove that