Question 35
Consider a triangle $ABC$ and its circumcircle. If $D$ and $E$ are points on side $BC$ such that $AD$ and $AE$ are, respectively, parallel to the tangents at $C$ and $B$ to the circumcircle, show that
$$
\frac{BE}{CD} = \frac{AB^2}{AC^2}
$$
$$
\frac{BE}{CD} = \frac{AB^2}{AC^2}
$$