Question 26
Let $ABCD$ be a parallelogram in the plane. We draw two circles of radius $R$, one through the points $A$ and $B$, the other through $B$ and $C$. Let $E$ be the other point of intersection of the circles. We assume that $E$ is not a vertex of the parallelogram. Show that the circle passing through $A$, $D$, and $E$ also has radius $R$.