Question 53
Let $x, y, z$ be non-negative numbers such that $x + 2y + 3z = \frac{11}{12}$. Prove that
$$
63xy + 4x + 2yz + 6x + 3y + 4z + 72xyz \leq \frac{17}{18}
$$
When does equality hold?
$$
63xy + 4x + 2yz + 6x + 3y + 4z + 72xyz \leq \frac{17}{18}
$$
When does equality hold?