Câu hỏi 111
Tìm tổng
$$
\frac{2^{1}}{4^{1}-1}+\frac{2^{2}}{4^{2}-1}+\frac{2^{4}}{4^{4}-1}+\frac{2^{8}}{4^{8}-1}+\cdots .
$$
$$
\frac{2^{1}}{4^{1}-1}+\frac{2^{2}}{4^{2}-1}+\frac{2^{4}}{4^{4}-1}+\frac{2^{8}}{4^{8}-1}+\cdots .
$$
MathNet 2005 — Phần 03 Câu hỏi 111
Math Olympiad Vault · MathNet 2005 — Phần 03