Question 55
Factorials. If $n$ is a natural number, we denote by $n!$ the product of all integers from 1 to $n$. For example: $5! = 1 \times 2 \times 3 \times 4 \times 5$ and $13! = 1 \times 2 \times 3 \times 4 \times 5 \times \ldots \times 12 \times 13$. By convention, $0! = 1$. Find three different integers $a$, $b$ and $c$, between 0 and 9, such that the three-digit number $abc$ is equal to $a! + b! + c!$.