Question 2
The base $AB$ of the trapezoid $ABCD$ is longer than the base $CD$, and $\angle ADC$ is a right angle. The diagonals $AC$ and $BD$ are perpendicular. Let $E$ be the foot of the altitude from $D$ to the line $BC$. Prove that $\frac{|AE|}{|BE|} = \frac{|AC| \cdot |CD|}{|AC|^2 - |CD|^2}$.