Question 62
For any positive real numbers $x, y, z$ with $xyz=1$ prove the following inequality:
$$
(-x+y+z)(x-y+z) + (x-y+z)(x+y-z) + (x+y-z)(-x+y+z) \le 3.
$$
$$
(-x+y+z)(x-y+z) + (x-y+z)(x+y-z) + (x+y-z)(-x+y+z) \le 3.
$$
Math Olympiad Vault · MathNet 2011