Question 82
Let $n$ be a composite positive integer and let $d_1, d_2, \dots, d_m$ be all of its divisors. Prove that the following equation holds:
$$
\frac{2}{\log n^m} \sum_{k=1}^{m} \log d_k = 1.
$$
$$
\frac{2}{\log n^m} \sum_{k=1}^{m} \log d_k = 1.
$$