Question 78
Do there exist pairwise distinct rational numbers $x$, $y$ and $z$ such that
$$
\frac{1}{(x - y)^2} + \frac{1}{(y - z)^2} + \frac{1}{(z - x)^2} = 2014?
$$
$$
\frac{1}{(x - y)^2} + \frac{1}{(y - z)^2} + \frac{1}{(z - x)^2} = 2014?
$$
Math Olympiad Vault · MathNet 2014