Question 92
Consider an acute angled triangle $AB\Gamma$, with $AB \lt A\Gamma$. Let $M$ be the midpoint of the side $B\Gamma$. On the side $AB$ we consider a point $\Delta$ such that, if the segment $\Gamma\Delta$ intersects the median $AM$ at point $E$, then $A\Delta = \Delta E$. Prove that $AB = \Gamma E$.