Question 54
Prove that if
$$
(n^2 + 1)^{2k} \cdot (44n^3 + 11n^2 + 10n + 2) = N^m
$$
holds for some non-negative integer values of $m$, $n$, $N$ and $k$, $m = 1$ must hold.
$$
(n^2 + 1)^{2k} \cdot (44n^3 + 11n^2 + 10n + 2) = N^m
$$
holds for some non-negative integer values of $m$, $n$, $N$ and $k$, $m = 1$ must hold.