Question 38
Solve the following system of equations in the set of rational numbers:
$$
\begin{aligned}
(x^2 + 1)^3 &= y + 1 \\
(y^2 + 1)^3 &= z + 1 \\
(z^2 + 1)^3 &= x + 1.
\end{aligned}
$$
$$
\begin{aligned}
(x^2 + 1)^3 &= y + 1 \\
(y^2 + 1)^3 &= z + 1 \\
(z^2 + 1)^3 &= x + 1.
\end{aligned}
$$