Question 8Square $ABCD$ has side $3$. Points $M,N,P,Q$ lie on $AB,BC,CD,DA$ with $AM=BN=CP=DQ=1$. Diagonal $BD$ meets $MN$ at $E$ and $PQ$ at $F$. Find $EF$. $\frac{3\sqrt3}{2}$$\sqrt3$$\sqrt2$$\frac{4\sqrt2}{3}$$\frac{5\sqrt2}{3}$