Question 3
In triangle $ABC$, $E$ and $D$ lie in the interiors of sides $AC$ and $BC$, respectively. In the figure, $AF$ bisects $\angle CAD$ and $BF$ bisects $\angle CBE$. Prove $$\angle AEB+\angle ADB=2\angle AFB.$$


SEAMO · SEAMO 2027 - Paper D - SET 09 - Self-study
