Question 62
Let $a, b, c$ be positive real numbers such that $abc = 1$. Prove that
$$
\frac{a+b+c+3}{4} \ge \frac{1}{a+b} + \frac{1}{b+c} + \frac{1}{c+a}.
$$
$$
\frac{a+b+c+3}{4} \ge \frac{1}{a+b} + \frac{1}{b+c} + \frac{1}{c+a}.
$$
MathNet 2015-part-04 — 191 problems (EN–VI) Question 62
Math Olympiad Vault · MathNet 2015-part-04 — 191 problems (EN–VI)