Question 97
In triangle $ABC$, the measures of the angles $B$ and $A$ are directly proportional to $2$ and $3$. Take $M$ and $N$ on the sides $[AB]$ and $[BC]$ respectively, so that $BN = NM = MC = MA$. Prove that:
a) one of the obtained triangles is equilateral;
b) $CM \perp AB$.
a) one of the obtained triangles is equilateral;
b) $CM \perp AB$.