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2011 AMC 12B Question 20

AMC12 · 2011 AMC 12B

Question 20

Triangle $ABC$ has $AB=13,$ $BC=14,$ and $AC=15.$ The points $D,$ $E,$ and $F$ are the midpoints of $AB,$ $BC,$ and $AC$ respectively. Let $X\ne E$ be the intersection of the circumcircles of $\triangle BDE$ and $\triangle CEF.$ What is $XA+XB+XC?$
  1. $24$
  2. $14\sqrt{3}$
  3. $\dfrac{195}{8}$
  4. $\dfrac{129\sqrt{7}}{14}$
  5. $\dfrac{69\sqrt{2}}{4}$