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2011 AMC 12A Question 19

AMC12 · 2011 AMC 12A

Question 19

At a competition with $N$ players, the number of players given elite status is equal to $$
2^{1 + \lfloor \log_2 (N - 1) \rfloor} - N.
$$ Suppose that $19$ players are given elite status. What is the sum of the two smallest possible values of $N?$

Note: $\lfloor x \rfloor$ is the greatest integer less than or equal to $x.$
  1. $38$
  2. $90$
  3. $154$
  4. $406$
  5. $1024$