Question 24A convex quadrilateral $ABCD$ with area $2002$ contains a point $P$ in its interior such that $PA=24,$ $PB=32,$ $PC=28,$ and $PD=45.$ Find the perimeter of $ABCD.$$4\sqrt{2002}$$2\sqrt{8465}$$2\left(48+\sqrt{2002}\right)$$2\sqrt{8633}$$4\left(36+\sqrt{113}\right)$