Câu hỏi 159
Chứng minh rằng nếu $a, b, c, d \in [1, 2]$ thì
$$
\frac{a+b}{b+c} + \frac{c+d}{d+a} \le 4 \cdot \frac{a+c}{b+d}.
$$
$$
\frac{a+b}{b+c} + \frac{c+d}{d+a} \le 4 \cdot \frac{a+c}{b+d}.
$$
Math Olympiad Vault · MathNet 2017-part-04 — 176 bài (EN–VI)