Question 25In triangle $ABC,$ $\angle ABC=120^\circ,$ $AB=3,$ and $BC=4.$ If perpendiculars constructed to $\overline{AB}$ at $A$ and to $\overline{BC}$ at $C$ meet at $D,$ then $CD=$$3$$\frac8{\sqrt3}$$5$$\frac{11}{2}$$\frac{10}{\sqrt3}$