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1992 AMC 12 Question 25

AMC12 · 1992 AMC 12

Question 25

In triangle $ABC,$ $\angle ABC=120^\circ,$ $AB=3,$ and $BC=4.$ If perpendiculars constructed to $\overline{AB}$ at $A$ and to $\overline{BC}$ at $C$ meet at $D,$ then $CD=$
  1. $3$
  2. $\frac8{\sqrt3}$
  3. $5$
  4. $\frac{11}{2}$
  5. $\frac{10}{\sqrt3}$