Question 28$ABCDE$ is a regular pentagon. $AP,$ $AQ$ and $AR$ are the perpendiculars dropped from $A$ onto $CD,$ $CB$ extended and $DE$ extended, respectively. Let $O$ be the center of the pentagon. If $OP=1,$ then $AO+AQ+AR$ equals $3$$1+\sqrt5$$4$$2+\sqrt5$$5$