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1986 AMC 12 Question 28

AMC12 · 1986 AMC 12

Question 28

$ABCDE$ is a regular pentagon. $AP,$ $AQ$ and $AR$ are the perpendiculars dropped from $A$ onto $CD,$ $CB$ extended and $DE$ extended, respectively. Let $O$ be the center of the pentagon. If $OP=1,$ then $AO+AQ+AR$ equals

Question illustration
  1. $3$
  2. $1+\sqrt5$
  3. $4$
  4. $2+\sqrt5$
  5. $5$