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1984 AMC 12 Question 11

AMC12 · 1984 AMC 12

Question 11

A calculator has a key which replaces the displayed entry with its square, and another key which replaces the displayed entry with its reciprocal. Let $y$ be the final result if one starts with an entry $x\ne0$ and alternately squares and reciprocates $n$ times each. Assuming the calculator is completely accurate (e.g., no roundoff or overflow), then $y$ equals
  1. $x^{(-2)^n}$
  2. $x^{2n}$
  3. $x^{-2n}$
  4. $x^{-2^n}$
  5. $x^{(-1)^n2n}$