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1966 AMC 12 Question 11

AMC12 · 1966 AMC 12

Question 11

The sides of triangle $BAC$ are in the ratio $2:3:4.$ $BD$ is the angle-bisector drawn to the shortest side $AC,$ dividing it into segments $AD$ and $CD.$ If the length of $AC$ is $10,$ then the length of the longer segment of $AC$ is:
  1. $3\dfrac12$
  2. $5$
  3. $5\dfrac57$
  4. $6$
  5. $7\dfrac12$