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VN TST 2017 Question 5

VMO · VN TST 2017

Question 5

Given 2017 positive real numbers $a_1,a_2,\ldots,a_{2017}$, define, for every $n>2017$,
$$a_n=\max\{a_{i_1}a_{i_2}a_{i_3}:i_1+i_2+i_3=n,\ 1\le i_1\le i_2\le i_3\le n-1\}.$$
Prove that there exist positive integers $m\le2017$ and $N>4m$ such that $a_na_{n-4m}=a_{n-2m}^2$ for all $n>N$.