Question 177
Let $ABC$ be a triangle and $P$ a point inside it. Lines $AP$, $BP$, $CP$ meet the opposite sides at $D$, $E$, $F$. Assume that the three quadrilaterals $PDCE$, $PEAF$, $PFBD$ are all bicentric. Prove that triangle $ABC$ is equilateral.
(A quadrilateral is bicentric if it can be inscribed inside a circle, and it also can have a circle inscribed inside it.)
(A quadrilateral is bicentric if it can be inscribed inside a circle, and it also can have a circle inscribed inside it.)