Question 57
Find an integral solution of the equation
$$
\left\lfloor \frac{x}{1!} \right\rfloor + \left\lfloor \frac{x}{2!} \right\rfloor + \left\lfloor \frac{x}{3!} \right\rfloor + \cdots + \left\lfloor \frac{x}{10!} \right\rfloor = 2019.
$$
(Note $\lfloor u \rfloor$ stands for the greatest integer less than or equal to $u$.)
$$
\left\lfloor \frac{x}{1!} \right\rfloor + \left\lfloor \frac{x}{2!} \right\rfloor + \left\lfloor \frac{x}{3!} \right\rfloor + \cdots + \left\lfloor \frac{x}{10!} \right\rfloor = 2019.
$$
(Note $\lfloor u \rfloor$ stands for the greatest integer less than or equal to $u$.)