Question 90
Let $ABC$ be a scalene triangle. Let $P$ be an interior point of $ABC$ such that $AP \perp BC$. Assume that $BP$ and $CP$ intersect $AC$ and $AB$ at $X$ and $Y$, respectively. Prove that $AX = AY$ iff there exists a circle with centre lying on $BC$ and tangent to $AB$ and $AC$ at points $Y$ and $X$, respectively.