Question 70
Prove that for an arbitrary positive integer $n$ the following inequality holds:
$$
\frac{1}{1^2 + 2019} + \frac{1}{2^2 + 2019} + \dots + \frac{1}{n^2 + 2019} \lt \frac{1}{22}.
$$
$$
\frac{1}{1^2 + 2019} + \frac{1}{2^2 + 2019} + \dots + \frac{1}{n^2 + 2019} \lt \frac{1}{22}.
$$