Question 5
Triangle $ABC$ has $AC = 450$ and $BC = 300.$ Points $K$ and $L$ are located on $\overline{AC}$ and $\overline{AB}$ respectively so that $AK = CK,$ and $\overline{CL}$ is the angle bisector of angle $C.$ Let $P$ be the point of intersection of $\overline{BK}$ and $\overline{CL},$ and let $M$ be the point on line $BK$ for which $K$ is the midpoint of $\overline{PM}.$ If $AM = 180,$ find $LP.$