Question 22
In the diagram below, the points $D,E,F$ lie on the lines $BC,AC,AB$ respectively. Given that $\angle EDC=\angle EFD$ and
$$\frac{ED}{AC}(AB^2-BC^2)+\frac{AB}{FD}(ED^2-EF^2)+AC\cdot ED+FD\cdot AB=0.$$
Given that $AF=24$, $BF=8$, $AE=16$, $CE=9$ and $BC=x$, find the value of $x$.
$$\frac{ED}{AC}(AB^2-BC^2)+\frac{AB}{FD}(ED^2-EF^2)+AC\cdot ED+FD\cdot AB=0.$$
Given that $AF=24$, $BF=8$, $AE=16$, $CE=9$ and $BC=x$, find the value of $x$.