Question 17
In the diagram below, ABCD is a trapezium in which AB // DC and AB = 10 cm. P is a point on BC such that BP = 4PC. Given that
$$\frac{\text{Area of }\triangle APD}{\text{Area of }\triangle APB}=\frac{15}{4},$$
find the length of DC in cm.
$$\frac{\text{Area of }\triangle APD}{\text{Area of }\triangle APB}=\frac{15}{4},$$
find the length of DC in cm.