Question 5
Assume that $(-1,0)$ is a point on the curve $y=ax^2+bx+c$, where $a,b,c$ are three fixed numbers not exceeding $\frac12$. If the inequality $x\le ax^2+bx+c\le\frac12(x^2+1)$ holds for all real numbers $x$, what is the value of $2020(a^2+b^2-c^2)$?