Question 8Two real numbers $u$ and $v$ satisfy the following equations respectively: $$2015u^2+2016u+1=0;\qquad v^2+2016v+2015=0.$$ If $uv\ne1$, find the value of $\frac uv$.$-\frac{2016}{2015}$$\frac1{2015}$$\frac1{2016}$$\frac{2016}{2015}$$1$