Question 19
Positive real numbers $x,y,z,\lambda$ satisfy
$$yz=6\lambda x,\qquad xz=6\lambda y,\qquad xy=6\lambda z,\qquad x^2+y^2+z^2=1.$$
Find $(xyz\lambda)^{-1}$.
$$yz=6\lambda x,\qquad xz=6\lambda y,\qquad xy=6\lambda z,\qquad x^2+y^2+z^2=1.$$
Find $(xyz\lambda)^{-1}$.