Question 15
$\triangle ABC$ is right-angled with $\angle ABC=90^\circ$. A circle $C_1$ is drawn with $AB$ as diameter, and another circle $C_2$ with $BC$ as diameter. The circles meet at $B$ and $P$. If $AB=5$ cm, $BC=12$ cm, and $BP=x$ cm, find $2400/x$.
