Question 77
Prove the following inequality for positive $a, b, c$:
$$
\frac{a^3 + b^3 + c^3}{abc} + 6 \ge 9 \cdot \frac{a^2 + b^2 + c^2}{ab + bc + ca}.
$$
$$
\frac{a^3 + b^3 + c^3}{abc} + 6 \ge 9 \cdot \frac{a^2 + b^2 + c^2}{ab + bc + ca}.
$$
MathNet 2020 — Math Olympiad Vault — Part 06 Question 77
Math Olympiad Vault · MathNet 2020 — Math Olympiad Vault — Part 06