Question 103
Let $ABC$ be a triangle and $D$ the point where its angle bisector from $A$ meets $BC$. Circle $\omega$ is tangent to $AC$ at $A$ and passes through $D$. Let $P$ be its second intersection with line $BC$. Given $AC=54$, $AD=63$, $CP=108$, find $AB$.
(A)72
(B)$147/2$
(C)98
(D)99
(E)102
(A)72
(B)$147/2$
(C)98
(D)99
(E)102