Question 120
Let $a = 256$. Find the unique real number $x \gt a^{2}$ such that
$$
\log_{a} \log_{a} \log_{a} x = \log_{a^{2}} \log_{a^{2}} \log_{a^{2}} x
$$
$$
\log_{a} \log_{a} \log_{a} x = \log_{a^{2}} \log_{a^{2}} \log_{a^{2}} x
$$
Math Olympiad Vault · MathNet 2020 — Math Olympiad Vault — Part 02