Question 39
A circle $c$ with center $A$ passes through the vertices $B$ and $E$ of a regular pentagon $ABCDE$. The line $BC$ intersects the circle $c$ the second time at point $F$. Point $G$ on the circle $c$ is chosen in such a way that $FB = FG$ and $B \neq G$. Prove that the lines $AB$, $EF$ and $DG$ meet in a common point.