Question 8
In triangle $ABC$, $\angle BAC=120^\circ$ and $\angle ABC=40^\circ$. Let $N$ be a point on $AC$ such that $AN=AB$. Let $M$ be a point on the line $BA$ such that $\angle ANM=40^\circ$, as shown in the diagram below. What is the measure, in degrees, of $\angle BMC$?
Paper instruction: Give a full solution.
Paper instruction: Give a full solution.