Question 44
Let $a,b,c$ be strictly positive real numbers satisfying $a+b+c=1$. Prove that
$$
\frac{1}{abc}+\frac{4}{a^2+b^2+c^2}\geq\frac{13}{ab+bc+ca}.
$$
$$
\frac{1}{abc}+\frac{4}{a^2+b^2+c^2}\geq\frac{13}{ab+bc+ca}.
$$
Math Olympiad Vault · MathNet 2021 — Part 10