Question 7
For every positive integer $N$, determine the smallest real number $b_N$ such that for every real $x$,
$$
\sqrt[N]{\frac{x^{2N}+1}{2}}\le b_N(x-1)^2+x.
$$
$$
\sqrt[N]{\frac{x^{2N}+1}{2}}\le b_N(x-1)^2+x.
$$
Math Olympiad Vault · MathNet 2021 — Part 09