Question 76
Let $a_{1}, \ldots, a_{101}$ be real numbers belonging to the interval $[-2 ; 10]$ such that
$$
a_{1}+\ldots+a_{101}=0
$$
Prove that
$$
a_{1}^{2}+\ldots+a_{101}^{2} \leqslant 2020
$$
$$
a_{1}+\ldots+a_{101}=0
$$
Prove that
$$
a_{1}^{2}+\ldots+a_{101}^{2} \leqslant 2020
$$