Question 48
For every natural number $x$, let $P(x)$ be the product of the digits of the number $x$. Is there a natural number $n$ such that the numbers $P(n)$ and $P(n^2)$ are non-zero squares of natural numbers, where the number of digits of the number $n$ is equal to
a. $2021$
b. $2022$
a. $2021$
b. $2022$