Question 186
In an acute triangle $ABC$ points $H$ and $O$ are the orthocenter and the circumcenter correspondingly. The line $HO$ intersects the sides $AB$ and $AC$ in points $X$ and $Y$ correspondingly, so that the point $H$ lies on the segment $OX$. It turned out that $XH = HO = OY$. Find the angle $\angle BAC$.
(Oleksii Masalitin)
(Oleksii Masalitin)