Câu hỏi 14
Biểu thức nào tương đương với biểu thức đã cho
$$
\frac{\sqrt[3]{4 a^{2} \cdot \sqrt[3]{a b} \cdot (a+b)^{0}}}{\left(8 b^{-2} \sqrt{a}\right)^{-\frac{2}{3}}}
$$
trong đó $a, b, a+b \neq 0$?
(A) $2^{\frac{8}{3}} a^{\frac{10}{9}} b^{-\frac{11}{9}}$
(B) $2^{\frac{2}{3}} a^{\frac{5}{6}} b^{\frac{4}{9}}$
(C) $2^{-3} a^{-\frac{5}{3}} b^{\frac{7}{9}}$
(D) $2^{-\frac{7}{6}} a^{-\frac{10}{3}} b^{\frac{5}{9}}$
(E) $2^{\frac{7}{3}} a^{-2} b^{\frac{1}{6}}$
$$
\frac{\sqrt[3]{4 a^{2} \cdot \sqrt[3]{a b} \cdot (a+b)^{0}}}{\left(8 b^{-2} \sqrt{a}\right)^{-\frac{2}{3}}}
$$
trong đó $a, b, a+b \neq 0$?
(A) $2^{\frac{8}{3}} a^{\frac{10}{9}} b^{-\frac{11}{9}}$
(B) $2^{\frac{2}{3}} a^{\frac{5}{6}} b^{\frac{4}{9}}$
(C) $2^{-3} a^{-\frac{5}{3}} b^{\frac{7}{9}}$
(D) $2^{-\frac{7}{6}} a^{-\frac{10}{3}} b^{\frac{5}{9}}$
(E) $2^{\frac{7}{3}} a^{-2} b^{\frac{1}{6}}$