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2012 AMC 10A Question 24

AMC10 · 2012 AMC 10A

Question 24

Let $a,$ $b,$ and $c$ be positive integers with $a\ge b\ge c$ such that $$
a^2-b^2-c^2+ab=2011
$$ and $$
a^2+3b^2+3c^2-3ab-2ac-2bc
$$$$
=-1997.
$$ What is $a?$
  1. $249$
  2. $250$
  3. $251$
  4. $252$
  5. $253$