Question 140
The sequence $\left(x_{n}\right)_{n=0}^{\infty}$ is defined by:
$$
x_{0}=1,\ x_{n+1}=x_{n}-\frac{x_{n}^{2}}{2023},\ n \in \mathbf{N}
$$
Prove that the sequence is convergent and $\lim _{n \rightarrow \infty} x_{n}=0$.
$$
x_{0}=1,\ x_{n+1}=x_{n}-\frac{x_{n}^{2}}{2023},\ n \in \mathbf{N}
$$
Prove that the sequence is convergent and $\lim _{n \rightarrow \infty} x_{n}=0$.